Dear Charles.

To make sure that I now understand look at my diagram.² The two : A, F in the hexagon the section of the Dodec.

Call CB radius of sphere (r) & CF radius of ⊙ in which the hexagon is inscribed r′, then

diag

r′ : r :: .8165 : 1 in the bees hexagon r′ = 0^inch.125 or ⅛ ^inch [therefore sign] r = r′.8165 = .125.8165

= 0^inch.153 r−r′ = 0^inch.028

distance sought.

The distance from center to obtuse ∠ = r

.866 = 0ⁱⁿ.153 .866 = 0ⁱⁿ.1325 distance to ob: ∠ of Dodec = 0.1325 r′ = distance to ∠ of Heg = 0.1250

Difference = 0.0075 or ¾ of $\frac{1}{100}$ inch.

ramme

Make no scruple of asking any number of explanations, as it is very little trouble to me, & saves you bother.³

Yours E D

[Enclosure]⁴

CB=R=1 CC’=R[SQUARE ROOT]2=1.414 EF=$\frac{1}{2}$FG=side of hexagon EF=EC [TIMES] tang 30^o=EC [TIMES] $\frac{1}{3}$ EF=EC=$\frac{2}{2}$ 2EF=FG=$\frac{2}{3}$= .8165 [DIAGRAMS HERE]